The Lua you need for FiveM, from zero

local money = 500          -- a number
local name = 'Mike'        -- a string
local onDuty = false       -- a boolean
local vehicle = nil        -- nothing yet

money = money + 250        -- reassign
print(name, money)         -- Mike 750

if money >= 1000 then
    print('rich')
elseif money > 0 then
    print('getting by')
else
    print('broke')
end

-- numeric: from 1 to 5
for i = 1, 5 do
    print(i)
end

-- counting down in steps
for i = 10, 0, -2 do print(i) end

-- over an array, in order
local jobs = { 'police', 'ambulance', 'mechanic' }
for index, job in ipairs(jobs) do
    print(index, job)
end

-- over any table (order not guaranteed)
local prices = { bread = 5, water = 2 }
for item, price in pairs(prices) do
    print(item, price)
end

-- while
local tries = 0
while tries < 3 do
    tries = tries + 1
end

local function fullName(first, last)
    return first .. ' ' .. last
end

-- Multiple return values are normal in Lua
local function minMax(a, b)
    if a < b then return a, b end
    return b, a
end

local lo, hi = minMax(9, 3)   -- 3, 9

-- Functions are values
local handlers = {
    greet = function(who) print('Hello ' .. who) end,
}
handlers.greet('Mike')

local plate = '  ab12cd  '
plate = plate:upper():gsub('%s+', '')   -- 'AB12CD'

print(('%s has $%d'):format('Mike', 250))  -- Mike has $250
print(('%.2f'):format(3.14159))             -- 3.14
print(#'hello')                             -- 5
print(('police'):sub(1, 3))                -- pol
print(('a,b,c'):find(','))                  -- 2 2